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What is the surface area produced by rotating $f (x) = 2 x^{2} + 4 x + 3, x \in [0, 3]$ $f(x)=2x^2+4x+3, x in [0,3]$ around the x-axis?

1 Answer

Aug 22, 2017

See below.

Explanation:

$V = \int_{0}^{3} π r^{2} d x$ $V =int_0^3 pi r^2 dx$

$= \int_{0}^{3} π {(2 x^{2} + 4 x + 3)}^{2} d x = \frac{19535 π}{3}$ $= int_0^3 pi (2x^2+4x+3)^2 dx = (19535pi)/3$

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