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What is the surface area produced by rotating $f (x) = x tan 2 x - tan x, x \in [\frac{π}{12}, \frac{11 π}{12}]$ $f(x)= xtan2x -tanx , x in [pi/12,(11pi)/12]$ around the x-axis?

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Frederico Guizini S.

May 26, 2018

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