Question

What is the vertex form of `3y = 5x^2+5x-12`?

Answer 1

`y=5/3(x+1/2)^2-53/12`

Explanation:

`y=5/3*x^2+5/3*x-4=5/3(x^2+x+1/4)-5/12-4=5/3(x+1/2)^2-53/12` Vertex is at `(-1/2,-53/12)` graph{5/3x^2+5/3x-4 [-10, 10, -5, 5]}[Ans]