Question

What is the vertex form of `5y=3x^2 -2x +8`?

Answer 1

`(1/3, 23/15)`

Explanation:

`5y=3x^2-2x+8`
`5y=3[x^2-(2/3)x]+8`
`5y=3[x^2-(2/3)x+(1/3)^2]+8-1/3`
`5y= 3(x-1/3)^2+23/3`
`y=3/5(x-1/3)^2+23/15` => in the vertex form of:
`y=a(x-h)^2+k` => where `(h, k)` is the vertex, thus the vertex is:
`(1/3, 23/15)`