Question

What is the vertex form of `y=2x^2+3x-8`?

Answer 1

Vertex form is `y = 2 (x + 3/4)^2 - 73/8`

Explanation:

`y = 2x^2 +3x -8 or y = 2 (x^2+3/2x) -8` or

`y = 2 (x^2+3/2x + (3/4)^2 ) - 2*9/16-8` or

`y = 2 (x + 3/4)^2 - 9/8-8` or

`y = 2 (x + 3/4)^2 - 73/8`

Vertex is `(-3/4 , -9 1/8)`

Vertex form is `y = 2 (x + 3/4)^2 - 73/8` [Ans]