What is the vertex form of $y = 2 x^{2} + 9 x - 5$ $y=2x^2+9x-5$ ?

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Answer 1 · 2018-06-25T11:47:44

Vertex form of equation is $y = 2 {(x + 2.25)}^{2} - 15.125$ $y=2( x +2.25)^2- 15.125$

$y = 2 x^{2} + 9 x - 5$ $y=2 x^2+9 x-5$ or

$y = 2 (x^{2} + 4.5 x) - 5$ $y=2( x^2+4.5 x) -5$ or

$y = 2 (x^{2} + 4.5 x + {2.25}^{2}) - 2 \cdot {2.25}^{2} - 5$ $y=2( x^2+4.5 x +2.25^2)- 2*2.25^2 -5$ or

$2 \cdot {2.25}^{2}$ $2*2.25^2$ is added and subtracted to get square.

$y = 2 {(x + 2.25)}^{2} - 15.125$ $y=2( x +2.25)^2- 15.125$

Vertex is at $- 2.25, - 15.125$ $-2.25,-15.125$

Vertex form of equation is $y = 2 {(x + 2.25)}^{2} - 15.125$ $y=2( x +2.25)^2- 15.125$ [Ans]

What is the vertex form of y=2x^2+9x-5 y=2x2+9x−5y=2x^2+9x-5 ?