What is the vertex form of #y=2x^2+9x-5 #?

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Answer 1 · 2018-06-25T11:47:44

Vertex form of equation is #y=2( x +2.25)^2- 15.125#

#y=2 x^2+9 x-5# or

#y=2( x^2+4.5 x) -5 # or

#y=2( x^2+4.5 x +2.25^2)- 2*2.25^2 -5 # or

#2*2.25^2# is added and subtracted to get square.

#y=2( x +2.25)^2- 15.125#

Vertex is at #-2.25,-15.125#

Vertex form of equation is #y=2( x +2.25)^2- 15.125# [Ans]