What is the vertex form of y=-3x^2 + 12x - 8?

1 Answer
Dec 21, 2016

The vertex form of y=-3x^2+12x-8 is y=-3(x-2)^2+4

Explanation:

To derive vertex form y=a(x-h)^2+k from general quadratic form y=ax^2+bx+c,
you can use completing the square

y=-3x^2+12x-8
= -3 (x^2-4x+8/3)
= -3 (x^2-4x +(-2)^2-(-2)^2 +8/3)
= -3 ((x-2)^2 -4+8/3)
= -3 ((x-2)^2 -4/3)
= -3 (x-2)^2 -4