What is the vertex form of #y= 4x^2 - 8x + 3 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Roella W. Dec 23, 2015 #y = 4(x-1)^2 -1# Explanation: Vertex form is #y = (ax +b)^2 +c# . In this case #a = 2# and #b = - 2# #(2x -2)^2 = 4x^2 - 8x + 4# so we need to subtract 1 #y = (2x-2)^2 -1# which is better expressed as #y = 4(x-1)^2 -1# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 4999 views around the world You can reuse this answer Creative Commons License