Question

What is the vertex form of `y= 4x^2 - x - 4`?

Answer 1

`y = 4(x - 1/8)^2 - 65/16`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = 1/8.`
y-coordinate of vertex:
`y(1/8) = 4(1/64) - 1/8 - 4 = 1/16 - 1/8 - 4 = -65/16`
`Vertex (1/8, -65/16)`
Vertex form of y:
`y = 4(x - 1/8)^2 - 65/16`