What is the vertex form of #y=x^2 -2x-15?

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Answer 1 · 2018-05-09T11:07:12

Vertex form of equation is #y= (x -1)^2 -16#

#y=x^2 -2 x -15 # or

#y=(x^2 -2 x + 1) -16 # or

#y=(x -1)^2 -16 # Comparing with vertex form of

equation #y = a(x-h)^2+k ; (h,k)# being vertex we find

here #h=1 , k= -16 :.# Vertex is at #(1,-16) # )# and vertex

form of equation is #y= (x -1)^2 -16#

graph{x^2-2x-15 [-40, 40, -20, 20]} [Ans]