What is the vertex form of #y=(x+2) (2x+5) #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Cem Sentin Dec 21, 2017 #y=2*(x+9/4)^2-1/8# Explanation: #y=(x+2)*(2x+5)# =#2x^2+9x+10# =#2*(x^2+9/2x+5)# =#2*(x^2+9/2x+(9/4)^2+5-(9/4)^2)# =#2*(x^2+9/2x+(9/4)^2-1/16)# =#2*(x+9/4)^2-1/16)# =#2*(x+9/4)^2-1/8# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1149 views around the world You can reuse this answer Creative Commons License