What is the vertex form of #y= x^2 – 3x – 40#?

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Answer 1 · 2016-02-28T04:49:01

#(x-3/2)^2=y+169/4" " "#the Vertex Form

From the given #y=x^2-3x-40# perform "Completing the square method#

#y=x^2-3x-40#

We add and subtract #9/4# to complete the square

#y=x^2-3x+9/4-9/4-40#

#y=(x-3/2)^2-169/4#

#y+169/4=(x-3/2)^2#

#(x-3/2)^2=y+169/4" " "#the Vertex Form

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