Question

What is the vertex form of `y=x^2+8x-1`?

Answer 1

The vertex form of `y=x^2+8x-1` is y=(x+4)^2-17.

Explanation:

First find `-b/2=-4`, so -4 will be added to x inside the parentheses.
Next, find `c-b^2` to find the value you add at the end.

`y = (x-b/2)^2+c-b^2`
`y=(x+4)^2-17`