What is the vertex form of #y=x^2+8x+14 #?
1 Answer
Jan 30, 2016
# y = (x + 4)^2 - 2#
Explanation:
the standard form of a parabola is
# y = ax^2 + bx + c# compare to
# y = x^2 + 8x + 14 # to obtain a = 1 , b= 8 and c = 14
The vertex form is :
# y =a (x - h )^2 + k # where (h , k ) are the coordinates of the vertex.
x-coord of vertex
#= - b/(2a) = -8/4 = - 2 # the y-coord =
#(-2)^2 + 8(-2) + 14 =8-16+ 14 = -2#
equation is :
in this question(see above ) a = 1
