What is the vertex form of y=(x+2)(x-2)?

1 Answer
Jun 20, 2017

y=x^2-4

Explanation:

" y has roots " x=+-2

"the x-coordinate of the vertex is at the midpoint of the roots"

rArrx_(color(red)"vertex")=(-2+2)/2=0

rArry_(color(red)"vertex")=(0+2)(0-2)=-4

"the equation of a parabola in "color(blue)"vertex form" is

• y=a(x-h)^2+k

"where " (h,k)" are the coordinates of the vertex and a is "
"a constant"

"here " (h,k)=(0,-4)" and " a=1

rArry=x^2-4larrcolor(red)" in vertex form"