What is the vertex form of y=(x+2)(x-2)?
1 Answer
Jun 20, 2017
Explanation:
" y has roots " x=+-2
"the x-coordinate of the vertex is at the midpoint of the roots"
rArrx_(color(red)"vertex")=(-2+2)/2=0
rArry_(color(red)"vertex")=(0+2)(0-2)=-4
"the equation of a parabola in "color(blue)"vertex form" is
• y=a(x-h)^2+k
"where " (h,k)" are the coordinates of the vertex and a is "
"a constant"
"here " (h,k)=(0,-4)" and " a=1
rArry=x^2-4larrcolor(red)" in vertex form"