What is the x intercept of #y= - 6/5x + 6#?

Question

2130 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-25T04:58:49

The x-intercept is #5#.

#y=-6/5x+6#

The x-intercept is the value of #x# when #y# is zero.

Substitute #0# for #y# in the equation.

#0=-6/5x+6#

Subtract #6# from both sides of the equation.

#-6=-6/5x+6-6=#

#-6=-6/5x#

Divide by #-6/5# on both sides. When dividing by a fraction, multiply times its reciprocal.

#-cancel(6^1)(-5/cancel6^1)=-cancel6^1/cancel5^1x(-cancel5^1/cancel6^1)#

#5=x#

Switch sides.

#x=5#

graph{y=-6/5x+6 [-16.02, 16.01, -8.01, 8.01]}