What is (x^2 + 3x -10) \div (x-2)(x2+3x−10)÷(x−2)?
1 Answer
Dec 19, 2017
Explanation:
"factorise the numerator"factorise the numerator
x^2+3x-10=(x+5)(x-2)x2+3x−10=(x+5)(x−2)
rArr(x^2+3x-10)/(x-2)⇒x2+3x−10x−2
=((x+5)cancel((x-2)))/cancel((x-2))=x+5
