Where is the vertex of the graph of $y = x^{2} + 4 x + 5$ $y = x^2 + 4x + 5$ located?

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Where is the vertex of the graph of $y = x^{2} + 4 x + 5$ $y = x^2 + 4x + 5$ located?

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Answer 1 · 2016-05-05T03:18:48

Vertex $(- 2, 1)$ $(-2, 1)$

Explanation:

Given -

$y = x^{2} + 4 x + 5$ $y=x^2+4x+5$
Find the $x$ $x$ co-ordinate of the vertex.
$x - \frac{- b}{2 a} = \frac{- 4}{2 \times 1} = \frac{- 4}{2} = - 2$ $x-(-b)/(2a)=(-4)/(2 xx 1)=(-4)/2=-2$
Find the $y$ $y$ co-ordinate
At $x = - 2; y = {(- 2)}^{2} + 4 (- 2) + 5$ $x=-2; y=(-2)^2+4(-2)+5$
$y = 4 - 8 + 5 = 9 - 8 = 1$ $y=4-8+5=9-8=1$
Vertex $(- 2, 1)$ $(-2, 1)$

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Where is the vertex of the graph of $y = x^{2} + 4 x + 5$ $y = x^2 + 4x + 5$ located?

1 Answer

Explanation:

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