Which conic section has the polar equation $r=1/(1-cosq)$ ?

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Answer 1 · 2018-04-08T00:09:45

parabola

if you meant theta instead of q:

$r=1/(1-cos(theta)$

$r-rcos(theta)=1$

$r=1+rcos(theta)$

$sqrt(x^2+y^2)=1+x$

$x^2+y^2=1+2x+x^2$

$y^2=1+2x$

$y^2/2-1/2=x$

^ a parabola opening to the right

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Which conic section has the polar equation r=1/(1-cosq)r=1/(1-cosq)?