Which conic section has the polar equation r=2/(3-cosq)?

1 Answer
Aug 18, 2016

8 x^2 + 9y^2-4 x-4=0

Explanation:

From r=2/(3-cosq)->3r-r cos q= 2

but r cos q = x and r^2 = x^2+y^2

so

3 r - x = 2->r = (x+2)/3 and also

r^2 = x^2+y^2=(x+2)^2/9

After some simplifications

8 x^2 + 9y^2-4 x-4=0

which is the equation of an ellipse