Which number is larger between #\frac{\pi}{15}# and #\frac{\sqrt{3}}{\sqrt{75}}#? Algebra Properties of Real Numbers Order of Real Numbers 1 Answer Wataru Oct 30, 2014 By #sqrt{75}=sqrt{5^2cdot3}=sqrt{5^2}cdot sqrt{3}=5sqrt{3}#, #{sqrt{3}}/{sqrt{75}}=sqrt{3}/{5sqrt{3}}=1/5=3/15#. Since #pi approx 3.14#, #sqrt{3}/sqrt{75}=3/15 le pi/15#. I hope that this was helpful. Answer link Related questions What are Real Numbers? What does it mean to order a set of real numbers? What are the different types of rational numbers? What kind of rational number is 0? How do you classify real numbers? How do you compare real numbers? What are examples of non real numbers? How would you categorize the number #\frac{\sqrt{36}}{9}#? How would you classify each of the following numbers: #\frac{\sqrt{12}}{2}, 1.5\cdot \sqrt{3},... How would you order the number from least to greatest: #\frac{\sqrt{6}}{2}, \frac{61}{50},... See all questions in Order of Real Numbers Impact of this question 4482 views around the world You can reuse this answer Creative Commons License