Why does the integral test not apply to Sigma (2+sinn)/n from [1,oo)?

1 Answer
Dec 28, 2016

Because the condition only applies if f(x) and a_n=f(n) are non-negative and monotone decreasing, which is not the case here.

Explanation:

In fact, if we choose:

f(x) = (2+sinx)/x

we have that the function is continuous and non-negative for x>0, but as:

f'(x) = frac(xcosx-2-sinx) (x^2)

is positive for some values of x, clearly f(x) is not monotone decreasing.

graph{(2+sinx)/x [-10, 10, -5, 5]}