How do you solve #3(x - 1) - 2(x + 3) = 0#?

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Answer 1 · 2014-09-28T17:45:18

#3( x-1) -2 (x+3) =0#

Distribute the #3# and the #-2#

#3*x -3*1 -2*x -2*3 = 0#

#3x -3 -2x -6 = 0#

Gather like terms

#3x -2x -3 -6 =0#

Combine like terms

#x -9 = 0#

adding #9# on both sides to get value of #x# ;

#x-9 + 9 = 0 +9 #

#x =9#