How do you solve #(c+3)-2c-(1-3c)=2#?

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Answer 1 · 2018-05-13T05:26:04

#c=0#

1) Remove brackets as they are the same operation (addition / subtraction)

#c+3-2c-1-3c=2#

2) Simplify the coefficient of c

#-4c+3-1=2#

3) Simplify the number

#-4c+2=2#

4) Subtract two from both sides

#-4c=0#

5) Divide both sides by -4

#c=0#