How do you solve $3(x - 1) - 2(x + 3) = 0$ ?

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Answer 1 · 2014-09-28T17:45:18

$3( x-1) -2 (x+3) =0$

Distribute the $3$ and the $-2$

$3*x -3*1 -2*x -2*3 = 0$

$3x -3 -2x -6 = 0$

Gather like terms

$3x -2x -3 -6 =0$

Combine like terms

$x -9 = 0$

adding $9$ on both sides to get value of $x$ ;

$x-9 + 9 = 0 +9$

$x =9$

How do you solve 3(x - 1) - 2(x + 3) = 03(x - 1) - 2(x + 3) = 0?