How do you find parametric equations for the tangent line to the curve with the given parametric equations #x=7t^2-4# and #y=7t^2+4# and #z=6t+5# and (3,11,11)?
1 Answer
Feb 22, 2015
The answer is:
The point
Now let's search the generic vector tangent to the curve:
So, for
So, remembering that given a point
so the tangent is:
N.B. The direction
that's simplier!