How do you factor by grouping $3 x^{3} + 2 x^{2} + 3 x + 2$ $3x^3+2x^2+3x+2$ ?

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Answer 1 · 2015-04-30T08:43:10

we are given, 3 $x^{3}$ $x^3$ $+$ $+$ 2 $x^{2}$ $x^2$ $+$ $+$ 3 $x$ $x$ $+$ $+$ 2

on rearrangement:

$=$ $=$ 3 $x^{3}$ $x^3$ $+$ $+$ 3 $x$ $x$ $+$ $+$ 2 $x^{2}$ $x^2$ $+$ $+$ 2

The first two terms have 3 $x$ $x$ in common and the last two terms have 2 in common:

taking out the common terms:
$=$ $=$ 3 $x$ $x$ ( $x^{2}$ $x^2$ + 1) $+$ $+$ 2 ( $x^{2}$ $x^2$ $+$ $+$ 1)

making groups of two:
$=$ $=$ (3 $x$ $x$ $+$ $+$ 2) ( $x^{2}$ $x^2$ $+$ $+$ 1 )

How do you factor by grouping 3x^3+2x^2+3x+23x3+2x2+3x+23x^3+2x^2+3x+2?