How do you graph $y = \sqrt{x - 1} - 3$ $y=sqrt(x-1)-3$ ?

Question

How do you graph $y = \sqrt{x - 1} - 3$ $y=sqrt(x-1)-3$ ?

1 Answer

Impact of this question

5748 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-06T13:10:34

Be $Y = y + 3$ $Y = y+3$ and $X = x - 1$ $X=x-1$

The function $Y = \sqrt{X}$ $Y=sqrtX$ has a domain going from
$X = 0$ $X=0$ to $X = + \infty$ $X=+oo$
and a range going from
$Y_{0} = \sqrt{0} = 0$ $Y_0 = sqrt0 = 0$ to $Y_{+ \infty} = \sqrt{+ \infty} = + \infty$ $Y_(+oo) = sqrt(+oo) = +oo$ .

Its curve is as represented bellow:

![http://mathworld.wolfram.com/SquareRoot.html]( useruploads.socratic.org )

However, $Y = y + 3 \leftrightarrow y = Y - 3$ $Y=y+3 harr y=Y-3$
therefore the $y = f (X)$ $y=f(X)$ curve will be identical to the $Y = f (X)$ $Y=f(X)$ curve, only with a negative vertical offset of 3.

enter image source here

Now $X = x - 1 \leftrightarrow x = X + 1$ $X=x-1 harr x=X+1$
therefore the $y = f (x)$ $y=f(x)$ curve will be identical to the $y = f (X)$ $y=f(X)$ curve, only with a positive horizontal offset of 1.

enter image source here

Science

Math

Humanities

... and beyond

How do you graph $y = \sqrt{x - 1} - 3$ $y=sqrt(x-1)-3$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you graph y=√x−1−3y=sqrt(x-1)-3?

1 Answer

Related questions

Impact of this question

How do you graph $y = \sqrt{x - 1} - 3$ $y=sqrt(x-1)-3$ ?