How do you solve #-2(x-4)=15#?

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Answer 1 · 2015-07-13T22:48:33

#x=7/(-2)#

We are given #-2(x-4)=15#

First, let's multiply the #-2# into what's inside the parenthesis:

#-2(x-4)=15#

#-2x-4*(-2)=15#

#-2x+8=15#

Now, let's subtract #8# from both sides:

#-2x+8=15#

#-2x=15-8#

#-2x=7#

Now, just divide both sides by #-2#

#-2x=7#

#x=7/(-2)#

Let's check and see if our answer is correct
by plugging in #x=7/(-2)# into #-2(x-4)=15#

#-2(x-4)=15#

#-2(-7/2-4)=15#

#-2(-7/2-8/2)=15#

#-2(-15/2)=15#

#15=15#