How do you solve $8 (4u - 1) - 12u = 11 (2u - 6)$ ?

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Answer 1 · 2015-09-27T22:53:24

You would begin by distributing the term outside of you parentheses and then combining your like terms.

$8(4u-1)-12u=11(2u-6)$
$8*4u$
$8*-1$
Left side should now look like this: $32u -8 -12u$
Right side:
$11*2u$
$11*-6$
Right side should now look like this: $22u-66$
Combine like terms and simplify:
$32u-8-12u=22u-66$
$32u-12u=20u$
$20u-8=22u-66$
Subtract $22u$ from both sides to combine and get $-2u$
Add $66$ to both sides so that way the $66$ on the right side cancels out and you get $58$ on the left side.
Final answer: $-2u+58$

How do you solve 8 (4u - 1) - 12u = 11 (2u - 6)8 (4u - 1) - 12u = 11 (2u - 6)?