How do you find the area of a trapezoid with base length 28, height 10, top side 8, and side lengths 12 and 15?

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How do you find the area of a trapezoid with base length 28, height 10, top side 8, and side lengths 12 and 15?

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Answer 1 · 2015-11-30T06:57:28

Area of the Trapezoid $= 180$ $= 180$

Explanation:

The Area of a Trapezoid is
$A = \frac{b_{1} + b_{2}}{2} \cdot h$ $A = {b_1 + b_2}/2 * h$

where $h$ $h$ is the height, $b_{1}$ $b_1$ is the base, and $b_{2}$ $b_2$ is the "top side"

in other words, the Area of a Trapezoid is the "Average of the Bases times the Height"

in this case,
$b_{1} = 28$ $b_1 = 28$
$b_{2} = 8$ $b_2 = 8$
and
$h = 10$ $h = 10$

which gives us
$A = \frac{28 + 8}{2} \cdot 10$ $A = {28+8}/2 * 10$
$A = \frac{36}{2} \cdot 10$ $A = 36/2 * 10$
$A = 18 \cdot 10$ $A = 18 * 10$
$A = 180$ $A = 180$ $\leftarrow$ $leftarrow$ answer

*note: the "side lengths" are unnecessary information

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How do you find the area of a trapezoid with base length 28, height 10, top side 8, and side lengths 12 and 15?

1 Answer

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