Find the area of a trapezoid with bases of 18 cm and 26 cm and a height of 11 cm?

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Find the area of a trapezoid with bases of 18 cm and 26 cm and a height of 11 cm?

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Answer 1 · 2015-12-01T18:11:52

$A r e a = 242 c m^{2}$ $Area = 242 cm^2$

Explanation:

The Area of a Trapezoid is represented by the equation:
$A r e a = \frac{b_{1} + b_{2}}{2} \cdot h$ $Area = frac{b_1+b_2}{2}*h$

where $b_{1} =$ $b_1 =$ one base
$b_{2} =$ $b_2 =$ the other base
and
$h =$ $h =$ the height

plugging this in will get us:
$A r e a = \frac{18 + 26}{2} \cdot 11$ $Area = frac{18+26}{2} * 11$
$A r e a = \frac{44}{2} \cdot 11$ $Area = frac{44}{2}*11$
$A r e a = 22 \cdot 11$ $Area = 22*11$
$A r e a = 242 \leftarrow$ $Area = 242 leftarrow$ answer

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Find the area of a trapezoid with bases of 18 cm and 26 cm and a height of 11 cm?

1 Answer

Explanation:

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