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What is the area of a kite with diagonals of 28ft and 13ft?

1 Answer

Dec 19, 2015

$182$ $182$ $f t^{2}$ $ft^2$

Explanation:

Area of kite is $A = \frac{d_{1} d_{2}}{2}$ $A=(d_1d_2)/2$

$d_{1} = 28$ $d_1=28$

$d_{2} = 13$ $d_2=13$

$A = \frac{28 (13)}{2}$ $A=(28(13))/2$

$A = \frac{364}{2}$ $A=364/2$

$A = 182$ $A=182$ $f t^{2}$ $ft^2$

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