Question

What is the trigonometric form of `12 e^( ( pi)/2 i )`?

Answer 1

`12isin(pi/2)`

Explanation:

`12e^(pi/2i)` is an imaginary number only you see this because `Arg(z) = pi/2` which is on imaginary line only

So `12e^(pi/2i) =12(cos(pi/2) + isin(pi/2)) = 12isin(pi/2) = 12i`

This is due to application of Euler's formula : `e^(itheta)=costheta+isintheta =cistheta`

You can see the graph