How do you simplify and state the excluded values for #(4x-4)/(x-1)#?

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Answer 1 · 2015-12-24T18:36:44

#(4x-4)/(x-1) = 4, x!= 1#

Given #(4x-4)/(x-1)#

Step 1: Factor the numerator

#(4(x-1))/(x-1)#

Step 2: Identify the excluded value by set the denominator to 0

# x-1 = 0#

#x = 1#

Step 3: Cancel the like term

#(4(cancel(x-1)))/cancel(x-1) , x!= 1#

Answer: #4, x!= 1#