If y varies directly with x, if x =9 when y = 18, how do you find x when y =24?

Question

If y varies directly with x, if x =9 when y = 18, how do you find x when y =24?

1 Answer

Impact of this question

6687 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-14T16:57:47

We can solve this using ration reasoning: $\frac{x_{2}}{x_{1}} = \frac{y_{2}}{y_{1}}$ $x_2/x_1=y_2/y_1$

Explanation:

If $x$ $x$ varies directly with $y$ $y$ (written $x \propto y$ $x prop y$ ), then doubling $y$ $y$ means doubling $x$ $x$ , so the rations of final values and initial values will be the same:

$\frac{x_{2}}{x_{1}} = \frac{y_{2}}{y_{1}}$ $x_2/x_1=y_2/y_1$

In this case,

$\frac{x_{2}}{9} = \frac{24}{18}$ $x_2/9=24/18$

$x_{2} = 9 \cdot \frac{24}{18} = 12$ $x_2=9*24/18 = 12$

Or, intuitively, if $x \propto y$ $x prop y$ and $x = 9$ $x = 9$ when $y = 18$ $y = 18$ , we can conclude that

$x = \frac{1}{2} y$ $x = 1/2y$

and $\frac{1}{2}$ $1/2$ of 24 is 12.

Science

Math

Humanities

... and beyond

If y varies directly with x, if x =9 when y = 18, how do you find x when y =24?

1 Answer

Explanation:

Related questions

Impact of this question