What are the components of the vector between the origin and the polar coordinate (2, (7pi)/4)(2,7π4)?

1 Answer
Feb 16, 2016

Components of this vector from the origin are
{sqrt 22, - sqrt 22j

Explanation:

r = 2 and thetaθ = 7pi7π/4.
The radial line thetaθ = 7piπ/4 bisects the fourth quadrant..
x = 2 cos 7pi7π/4 =2 cos (2pi - pi2ππ/4) = 2 cos (piπ/4) = sqrt 2. Similarly, y = 2 sin 7pi7π/4 =2sin (2pi - pi2ππ/4) = - 2 sin (piπ/4) = - sqrt2.
The given radial vector has components (x, y) = (sqrt2, - sqrt2)