The combustion of butane, C4H10, produces carbon dioxide water. When one sample of butane was burned, 4.46 grams of water was formed. How many grams of oxygen gas were consumed?

1 Answer
Wil052 · Stefan V. · Jarni Renz
Mar 3, 2016

10.3 g O2

Explanation:

Combustion reactions with hydrocarbons (compounds made up of only carbon and hydrogen, C4H10) involve the hydrocarbon reacting with O2 gas to form H2O and CO2

We must first balance the equation, we end up with;

2C4H10+13O2→10H2O+8CO2

with the balanced equation, most of the work is done. We now simply convert from H2O to O2 using the mol to mol ratios.

H=1.01 g
O=16.00 g
H2O=18.02 g
O2=32.00 g

4.46 g H2O×1 mol H2O18.02 g H2O×13 mol O210 mol H2O×32.0 g O21 mol O2=10.3 g O2 gas

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