Question

How do you find the standard form of `x^2-y^2=9` and what kind of a conic is it?

Answer 1

`x^2/9 - y^2/9 = 1`

Explanation:

Since the coefficient of `x^2` and `y^2` have different signs, we are dealing with a hyperbola.

To transform it into standard form, we need to make the right hand side of the equation equal to 1. To do this, we simply divide both sides of the equation by 9.

`(x^2 - y^2)/9 = 9/9`

`=> x^2/9 - y^2/9 = 1`