How do you solve $2(13t-15)+3(t-19)=0$ ?

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Answer 1 · 2016-05-31T04:14:45

$t=3$

First distribute the 2 and 3 into their respective binomials. This yields

$(26t-30)+(3t-57)=0$

Now drop the parentheses and simplify to

$29t-87=0$

Now you can solve for t by adding 87 to both sides to get

$29t=87$

and dividing both sides by 29

$t=87/29=3$

You can check this answer by plugging it back into the original equation:

$2(13(3)-15)+3(3-19)=2(24)+3(-16)=48-48=0$

How do you solve 2(13t-15)+3(t-19)=02(13t-15)+3(t-19)=0?