How do you solve $2 (x - 5) = - 11$ $2(x-5)=-11$ ?

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Answer 1 · 2016-06-22T14:11:21

$x = - \frac{1}{2}$ $color(blue)(x = -1/2$

$2 (x - 5) = - 11$ $2 ( x - 5) = -11$

$2 \cdot (x) + 2 \cdot (- 5) = - 11$ $2 * ( x) + 2 * ( - 5) = -11$

$2 x - 10 = - 11$ $2 x - 10 = -11$

$2 x = - 11 + 10$ $2 x = -11 + 10$

$2 x = - 1$ $2x =- 1$

$x = - \frac{1}{2}$ $color(blue)(x = -1/2$

How do you solve 2(x−5)=−112(x-5)=-11?