Question #08917

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Question #08917

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Answer 1 · 2017-02-04T19:40:14

1
$0.3 \cdot 1.204 \cdot 10^{24} = 3.612 \cdot 10^{23}$ $0.3 * 1.204 * 10^24 = 3.612 * 10^23$ H atoms
$0.7 \cdot 1.204 \cdot 10^{24} = 8.428 \cdot 10^{23}$ $0.7 * 1.204 * 10^24 = 8.428 * 10^23$ atoms of unknown element

2
$3.612 \cdot 10^{23}$ $3.612 * 10^23$ H atoms $\cdot \frac{1}{6.022 \cdot 10^{23}}$ $* 1/(6.022 * 10^23)$ mol/atoms $\cdot \frac{1.01}{1}$ $* 1.01/1$ g/mol = 0.606g

So, $57.14 - 0.606$ $57.14 - 0.606$ = 56.53g

3
$8.428 \cdot 10^{23} \cdot \frac{1}{6.022 \cdot 10^{23}} = 1.3995$ $8.428 * 10^23 * 1/(6.022 * 10^23) = 1.3995$ mol of unknown element

Molar mass = $\frac{56.53}{1.3995} = 40.3$ $56.53/1.3995 = 40.3$ gmol

With slight error, this is the molar mass of argon on the periodic table (i.e 39.95 g/mol).

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Question #08917

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