How do you factor #2b^3+3b^2-8b-12# by grouping?
1 Answer
Feb 9, 2017
Explanation:
- If you try to find a connection between 2, 3, 8 and 12. You will find that 2 is the common factor of 2 and 8; 3 is the common factor or 3 and 12.
2.So try group them like above and you will get:
-
And here comes the answer:
#(2b+3)(b^2-4)# -
You can further break
#(b^2-4)# into#(b+2)(b-2)# -
The final result is :
#(2b+3)(b+2)(b-2)#