How many grams of CO are needed to to produce 442 grams of Fe? $1Fe_2O_3 + 3CO -> 3CO_2 + 2Fe$

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Answer 1 · 2017-04-05T05:09:00

331.5 g of CO are needed.

$n mol Fe = m/( MW) = (442 g)/(56 g/(mol)) = 7.89 mol$

$n mol CO = 7.89 mol Fe * ((3 mol CO)/(2 mol Fe)) = 11.84 mol CO$

$mass CO = n * MW = 11.84 mol * (28 g)/(mol) = 331.5 g CO$

How many grams of CO are needed to to produce 442 grams of Fe? 1Fe_2O_3 + 3CO -> 3CO_2 + 2Fe1Fe_2O_3 + 3CO -> 3CO_2 + 2Fe