Question #19845

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Answer 1 · 2017-05-01T07:13:40

The first step to solving such questions would be writing the chemical equations.

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Given that there is $5.85g$ $"5.85g"$ of calcium chloride, and that the molar mass of calcium chloride is

$40.08 + (2 \times 35.45) = {110.98 gmol}^{- 1}$ $40.08 + (2 xx 35.45) = "110.98 gmol"^(-1)$

the amount of calcium chloride in moles is

$\frac{5.85 g}{{110.98 gmol}^{- 1}} = 0.052712 moles$ $"5.85 g"/"110.98 gmol"^(-1) = "0.052712 moles"$

By molar ratio, the amount of sodium chloride formed in moles is $0.052712$ $0.052712$ moles.

The molar mass of sodium chloride is

$22.99 + 35.45 = {58.44 gmol}^{- 1}$ $22.99 + 35.45 = "58.44 gmol"^(-1)$

The mass of sodium chloride formed is

$0.052712 moles \times {58.44 gmol}^{- 1} = 3.08 g$ $"0.052712 moles" xx "58.44 gmol"^(-1) = "3.08 g"$

Perhaps taking note of the units can help you to find answers; for example:

$mol \times {gmol}^{- 1}$ $"mol" xx "gmol"^(-1)$

gives the answer is grams (the mass) and so on and so forth!