Question #f1fb8

1 Answer
AA_123
May 19, 2017

#(+50)# or #(8xx10^-18C)#

Explanation:

It was neutral with #500# electrons, if it has lost #10%# electrons, then it has lost #50# electrons (#10%# is the same as #10/100# which is #0.1#, #500xx0.1=color(green)50#)

If it has "lost" #color(green)50#" electron" then its charge will be #+color(green)50# (each electron is #-1# "lost")

Or in Coulombs the charge will be #color(red)(1.6xx10^-19)*color(green)50# which is #8xx10^-18C# (because each electron is #-1.6xx10^-19C# in charge)

Related questions
See all questions in Net Charge
Impact of this question
1665 views around the world
You can reuse this answer
Creative Commons License