How much energy is required to melt 1.5 kg of lead?

1 Answer
Jun 6, 2017

34.5334.53kJ

Explanation:

The enthalpy of fusion (energy need to change state from solid to liquid) of lead is 4.77 kJ/mol (so it takes 4.77 kJ to melt one mole of lead).
We need to find the number of moles (nn) of lead in 1.5kg (mm).

n=m/Mn=mM
From periodic table, M=207.2g/mol
Therefore, n=(1500g)/(207.2g.mol^-1)n=1500g207.2g.mol1
n=7.24n=7.24 moles
Energy =7.24=7.24moles*4.77kJ.mol^-14.77kJ.mol1
Energy 34.5334.53kJ