How do you multiply (2x-3y)^2?
1 Answer
The answer is
Explanation:
First, we begin by setting it in the form of
(2x-3y)(2x-3y)
Using FOIL, we multiply the first term with the outer and inner term of
4x^2-6xy
Now we do the same for the last term of the first part so
-6xy+9y^2
So we now have the following terms of
4x^2-6xy-6xy+9y^2
What we do now is simplify (combine like terms). The final answer is
4x^2-12xy+9y^2