How do you multiply $(2x-3y)^2$ ?

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Answer 1 · 2017-06-06T21:29:24

The answer is $4x^2-12xy+9y^2$ .

First, we begin by setting it in the form of

$(2x-3y)(2x-3y)$

Using FOIL, we multiply the first term with the outer and inner term of $(2x)(2x-3y)$ . If done right, you should arrive to the answer of

$4x^2-6xy$

Now we do the same for the last term of the first part so $(-3y)(2x-3y)$ . The answer should be

$-6xy+9y^2$

So we now have the following terms of

$4x^2-6xy-6xy+9y^2$

What we do now is simplify (combine like terms). The final answer is

$4x^2-12xy+9y^2$

How do you multiply (2x-3y)^2(2x-3y)^2?