How do you factor $8 x^{3} - 8 x^{2} - x + 1$ $8x^3 - 8x^2 - x + 1$ by grouping?

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How do you factor $8 x^{3} - 8 x^{2} - x + 1$ $8x^3 - 8x^2 - x + 1$ by grouping?

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Answer 1 · 2017-06-09T09:01:37

$8 x^{3} - 8 x^{2} - x + 1$ $8x^3-8x^2-x+1$
Take $8 x^{2}$ $8x^2$ common from first two terms and $- 1$ $-1$ from the last two terms.
$= 8 x^{2} (x - 1) - 1 (x - 1)$ $=8x^2(x-1)-1(x-1)$
Take the factor $(x - 1)$ $(x-1)$ as common.
$= (x - 1) (8 x^{2} - 1)$ $=(x-1)(8x^2-1)$

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How do you factor $8 x^{3} - 8 x^{2} - x + 1$ $8x^3 - 8x^2 - x + 1$ by grouping?

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