How do you multiply #(2x^2+8)div(x^4-16)/(x^2+x-6)#?
1 Answer
Explanation:
Take into account the formula:
We can apply this formula one more for
We can also do something with
formula for quadratic function:
where
We can use the following method only when a=1. In this particular example b=1 and c=-6
in order to get solution we have to:
The only way how to get 6 is by multiplying 61 or 32 then we have to resolve signs from the second equation
There is no way we can arrange 6 and 1 to get 1. so the solution is 3 and 2 and it's:
Now we can rewrite: